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14421113333 = 111311010303
BaseRepresentation
bin11010110111001000…
…01011100111110101
31101020000212110110122
431123210023213311
5214013301111313
610342554301325
71020240304124
oct153344134765
941200773418
1014421113333
116130384990
122965727845
13148a933573
149ab3b5abb
155960b7708
hex35b90b9f5

14421113333 has 4 divisors (see below), whose sum is σ = 15732123648. Its totient is φ = 13110103020.

The previous prime is 14421113323. The next prime is 14421113351. The reversal of 14421113333 is 33331112441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14421113333 - 212 = 14421109237 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14421113323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 655505141 + ... + 655505162.

It is an arithmetic number, because the mean of its divisors is an integer number (3933030912).

Almost surely, 214421113333 is an apocalyptic number.

It is an amenable number.

14421113333 is a deficient number, since it is larger than the sum of its proper divisors (1311010315).

14421113333 is a wasteful number, since it uses less digits than its factorization.

14421113333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1311010314.

The product of its digits is 2592, while the sum is 26.

Adding to 14421113333 its reverse (33331112441), we get a palindrome (47752225774).

The spelling of 14421113333 in words is "fourteen billion, four hundred twenty-one million, one hundred thirteen thousand, three hundred thirty-three".

Divisors: 1 11 1311010303 14421113333