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144212023303 = 145511991073
BaseRepresentation
bin1000011001001110110…
…1001101100000000111
3111210020101100211111021
42012103231031200013
54330321234221203
6150130004052011
713263464654425
oct2062355154007
9453211324437
10144212023303
1156183a22637
1223b48394007
13107a33ba48a
146da0bb4115
153b408c85bd
hex2193b4d807

144212023303 has 4 divisors (see below), whose sum is σ = 144213159888. Its totient is φ = 144210886720.

The previous prime is 144212023259. The next prime is 144212023327. The reversal of 144212023303 is 303320212441.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 144212023303 - 29 = 144212022791 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (144212023393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 350026 + ... + 641047.

It is an arithmetic number, because the mean of its divisors is an integer number (36053289972).

Almost surely, 2144212023303 is an apocalyptic number.

144212023303 is a deficient number, since it is larger than the sum of its proper divisors (1136585).

144212023303 is an equidigital number, since it uses as much as digits as its factorization.

144212023303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1136584.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 144212023303 its reverse (303320212441), we get a palindrome (447532235744).

The spelling of 144212023303 in words is "one hundred forty-four billion, two hundred twelve million, twenty-three thousand, three hundred three".

Divisors: 1 145511 991073 144212023303