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14421311014111 = 17098438449979
BaseRepresentation
bin1101000111011011100100…
…0111101100010011011111
31220001122220221221000021021
43101312321013230103133
53342234321104422421
650401020412145011
73015622350031051
oct321667107542337
956048827830237
1014421311014111
114660053117341
12174ab43a68167
13807c017601c1
1437bdd0aa38d1
151a01e86cb341
hexd1db91ec4df

14421311014111 has 4 divisors (see below), whose sum is σ = 14429749465800. Its totient is φ = 14412872562424.

The previous prime is 14421311014067. The next prime is 14421311014147. The reversal of 14421311014111 is 11141011312441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14421311014111 - 211 = 14421311012063 is a prime.

It is a super-2 number, since 2×144213110141112 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14421311014151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4219223281 + ... + 4219226698.

It is an arithmetic number, because the mean of its divisors is an integer number (3607437366450).

Almost surely, 214421311014111 is an apocalyptic number.

14421311014111 is a deficient number, since it is larger than the sum of its proper divisors (8438451689).

14421311014111 is an equidigital number, since it uses as much as digits as its factorization.

14421311014111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8438451688.

The product of its (nonzero) digits is 384, while the sum is 25.

Adding to 14421311014111 its reverse (11141011312441), we get a palindrome (25562322326552).

The spelling of 14421311014111 in words is "fourteen trillion, four hundred twenty-one billion, three hundred eleven million, fourteen thousand, one hundred eleven".

Divisors: 1 1709 8438449979 14421311014111