Base | Representation |
---|---|
bin | 100000110010110100110001… |
… | …001100110010010110000111 |
3 | 200220200021011012110100201111 |
4 | 200302310301030302112013 |
5 | 122401031242240440003 |
6 | 1230430223050305451 |
7 | 42244165611531451 |
oct | 4062646114622607 |
9 | 626607135410644 |
10 | 144230122202503 |
11 | 41a57718a03647 |
12 | 14214920128287 |
13 | 6262ac430895c |
14 | 2788abd0872d1 |
15 | 11a1b53132e6d |
hex | 832d31332587 |
144230122202503 has 2 divisors, whose sum is σ = 144230122202504. Its totient is φ = 144230122202502.
The previous prime is 144230122202471. The next prime is 144230122202609. The reversal of 144230122202503 is 305202221032441.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 144230122202503 - 25 = 144230122202471 is a prime.
It is a super-3 number, since 3×1442301222025033 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (144230122502503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72115061101251 + 72115061101252.
It is an arithmetic number, because the mean of its divisors is an integer number (72115061101252).
Almost surely, 2144230122202503 is an apocalyptic number.
144230122202503 is a deficient number, since it is larger than the sum of its proper divisors (1).
144230122202503 is an equidigital number, since it uses as much as digits as its factorization.
144230122202503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 144230122202503 its reverse (305202221032441), we get a palindrome (449432343234944).
The spelling of 144230122202503 in words is "one hundred forty-four trillion, two hundred thirty billion, one hundred twenty-two million, two hundred two thousand, five hundred three".
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