Base | Representation |
---|---|
bin | 1101000111100010000001… |
… | …1010111110010111110111 |
3 | 1220001211101202002000111011 |
4 | 3101320200122332113313 |
5 | 3342301343243401403 |
6 | 50401504402453051 |
7 | 3016013323145041 |
oct | 321704032762767 |
9 | 56054352060434 |
10 | 14423044122103 |
11 | 4660862442aa1 |
12 | 174b348364187 |
13 | 80811982c2a6 |
14 | 37c116d26a91 |
15 | 1a029a91ea6d |
hex | d1e206be5f7 |
14423044122103 has 2 divisors, whose sum is σ = 14423044122104. Its totient is φ = 14423044122102.
The previous prime is 14423044122077. The next prime is 14423044122143. The reversal of 14423044122103 is 30122144032441.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (30122144032441) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14423044122103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14423044122143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7211522061051 + 7211522061052.
It is an arithmetic number, because the mean of its divisors is an integer number (7211522061052).
Almost surely, 214423044122103 is an apocalyptic number.
14423044122103 is a deficient number, since it is larger than the sum of its proper divisors (1).
14423044122103 is an equidigital number, since it uses as much as digits as its factorization.
14423044122103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 14423044122103 its reverse (30122144032441), we get a palindrome (44545188154544).
The spelling of 14423044122103 in words is "fourteen trillion, four hundred twenty-three billion, forty-four million, one hundred twenty-two thousand, one hundred three".
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