Base | Representation |
---|---|
bin | 100000110010111110000101… |
… | …010110101111011111101111 |
3 | 200220201012222020122222211022 |
4 | 200302332011112233133233 |
5 | 122401212233223024012 |
6 | 1230434555340244355 |
7 | 42245001510636242 |
oct | 4062760526573757 |
9 | 626635866588738 |
10 | 144240124033007 |
11 | 41a60990758972 |
12 | 142168518406bb |
13 | 6263a294b7362 |
14 | 278938b565259 |
15 | 11a203b253472 |
hex | 832f855af7ef |
144240124033007 has 2 divisors, whose sum is σ = 144240124033008. Its totient is φ = 144240124033006.
The previous prime is 144240124032989. The next prime is 144240124033009. The reversal of 144240124033007 is 700330421042441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 144240124033007 - 212 = 144240124028911 is a prime.
Together with 144240124033009, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (144240124033009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72120062016503 + 72120062016504.
It is an arithmetic number, because the mean of its divisors is an integer number (72120062016504).
Almost surely, 2144240124033007 is an apocalyptic number.
144240124033007 is a deficient number, since it is larger than the sum of its proper divisors (1).
144240124033007 is an equidigital number, since it uses as much as digits as its factorization.
144240124033007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64512, while the sum is 35.
Adding to 144240124033007 its reverse (700330421042441), we get a palindrome (844570545075448).
The spelling of 144240124033007 in words is "one hundred forty-four trillion, two hundred forty billion, one hundred twenty-four million, thirty-three thousand, seven".
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