Search a number
-
+
144302545433 = 991145613063
BaseRepresentation
bin1000011001100100011…
…0100001101000011001
3111210110200200211111202
42012121012201220121
54331012422423213
6150143000203545
713265644253354
oct2063106415031
9453420624452
10144302545433
1156220030212
1223b727695b5
13107b9092c77
146dacc1929b
153b48809b58
hex21991a1a19

144302545433 has 4 divisors (see below), whose sum is σ = 144448159488. Its totient is φ = 144156931380.

The previous prime is 144302545423. The next prime is 144302545441. The reversal of 144302545433 is 334545203441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 144302545433 - 24 = 144302545417 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (144302545403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72805541 + ... + 72807522.

It is an arithmetic number, because the mean of its divisors is an integer number (36112039872).

Almost surely, 2144302545433 is an apocalyptic number.

It is an amenable number.

144302545433 is a deficient number, since it is larger than the sum of its proper divisors (145614055).

144302545433 is an equidigital number, since it uses as much as digits as its factorization.

144302545433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 145614054.

The product of its (nonzero) digits is 345600, while the sum is 38.

Adding to 144302545433 its reverse (334545203441), we get a palindrome (478847748874).

The spelling of 144302545433 in words is "one hundred forty-four billion, three hundred two million, five hundred forty-five thousand, four hundred thirty-three".

Divisors: 1 991 145613063 144302545433