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144310112231 is a prime number
BaseRepresentation
bin1000011001100110001…
…1011000111111100111
3111210111012221021012112
42012121203120333213
54331021342042411
6150143430311235
713266065500115
oct2063143307747
9453435837175
10144310112231
115622432926a
1223b751b851b
13107ba81216c
146dadc28ab5
153b49301b8b
hex21998d8fe7

144310112231 has 2 divisors, whose sum is σ = 144310112232. Its totient is φ = 144310112230.

The previous prime is 144310112209. The next prime is 144310112251. The reversal of 144310112231 is 132211013441.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-144310112231 is a prime.

It is a super-2 number, since 2×1443101122312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 144310112197 and 144310112206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144310112201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72155056115 + 72155056116.

It is an arithmetic number, because the mean of its divisors is an integer number (72155056116).

Almost surely, 2144310112231 is an apocalyptic number.

144310112231 is a deficient number, since it is larger than the sum of its proper divisors (1).

144310112231 is an equidigital number, since it uses as much as digits as its factorization.

144310112231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 144310112231 its reverse (132211013441), we get a palindrome (276521125672).

The spelling of 144310112231 in words is "one hundred forty-four billion, three hundred ten million, one hundred twelve thousand, two hundred thirty-one".