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144324500035 = 528864900007
BaseRepresentation
bin1000011001101001101…
…0010001101001000011
3111210112020000020120011
42012122122101221003
54331034033000120
6150145102525351
713266332003062
oct2063232215103
9453466006504
10144324500035
1156231466011
1223b79b96857
13107c07abc61
146db1ad21d9
153b4a6e4c5a
hex219a691a43

144324500035 has 4 divisors (see below), whose sum is σ = 173189400048. Its totient is φ = 115459600024.

The previous prime is 144324499993. The next prime is 144324500051. The reversal of 144324500035 is 530005423441.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 530005423441 = 1340769647957.

It is a cyclic number.

It is not a de Polignac number, because 144324500035 - 217 = 144324368963 is a prime.

It is a super-2 number, since 2×1443245000352 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14432449999 + ... + 14432450008.

It is an arithmetic number, because the mean of its divisors is an integer number (43297350012).

Almost surely, 2144324500035 is an apocalyptic number.

144324500035 is a deficient number, since it is larger than the sum of its proper divisors (28864900013).

144324500035 is an equidigital number, since it uses as much as digits as its factorization.

144324500035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28864900012.

The product of its (nonzero) digits is 28800, while the sum is 31.

Adding to 144324500035 its reverse (530005423441), we get a palindrome (674329923476).

The spelling of 144324500035 in words is "one hundred forty-four billion, three hundred twenty-four million, five hundred thousand, thirty-five".

Divisors: 1 5 28864900007 144324500035