Base | Representation |
---|---|
bin | 100000110100010010110110… |
… | …011010000100011101111110 |
3 | 200221000220220101201022212021 |
4 | 200310102312122010131332 |
5 | 122404210134133132032 |
6 | 1230544451100230354 |
7 | 42254403141650104 |
oct | 4064226632043576 |
9 | 627026811638767 |
10 | 144331141302142 |
11 | 41a96547618353 |
12 | 1423041323b3ba |
13 | 626c4a2cb1c22 |
14 | 278d9435c7c74 |
15 | 11a45b6a73097 |
hex | 8344b668477e |
144331141302142 has 8 divisors (see below), whose sum is σ = 218929259278800. Its totient is φ = 71354721542544.
The previous prime is 144331141302109. The next prime is 144331141302221. The reversal of 144331141302142 is 241203141133441.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 144331141302098 and 144331141302107.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 405424554042 + ... + 405424554397.
It is an arithmetic number, because the mean of its divisors is an integer number (27366157409850).
Almost surely, 2144331141302142 is an apocalyptic number.
144331141302142 is a deficient number, since it is larger than the sum of its proper divisors (74598117976658).
144331141302142 is an equidigital number, since it uses as much as digits as its factorization.
144331141302142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 810849108530.
The product of its (nonzero) digits is 27648, while the sum is 34.
Adding to 144331141302142 its reverse (241203141133441), we get a palindrome (385534282435583).
The spelling of 144331141302142 in words is "one hundred forty-four trillion, three hundred thirty-one billion, one hundred forty-one million, three hundred two thousand, one hundred forty-two".
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