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14433139997 is a prime number
BaseRepresentation
bin11010111000100100…
…00011110100011101
31101020212111110221122
431130102003310131
5214024340434442
610344104140325
71020444444233
oct153422036435
941225443848
1014433139997
116137149781
1229697676a5
131490284733
149acc26953
15597190dd2
hex35c483d1d

14433139997 has 2 divisors, whose sum is σ = 14433139998. Its totient is φ = 14433139996.

The previous prime is 14433139979. The next prime is 14433140003. The reversal of 14433139997 is 79993133441.

14433139997 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (14433139979) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7400472676 + 7032667321 = 86026^2 + 83861^2 .

It is a cyclic number.

It is not a de Polignac number, because 14433139997 - 214 = 14433123613 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14433139937) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7216569998 + 7216569999.

It is an arithmetic number, because the mean of its divisors is an integer number (7216569999).

Almost surely, 214433139997 is an apocalyptic number.

It is an amenable number.

14433139997 is a deficient number, since it is larger than the sum of its proper divisors (1).

14433139997 is an equidigital number, since it uses as much as digits as its factorization.

14433139997 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2204496, while the sum is 53.

The spelling of 14433139997 in words is "fourteen billion, four hundred thirty-three million, one hundred thirty-nine thousand, nine hundred ninety-seven".