14434113223421 has 4 divisors (see below), whose sum is σ = 14446273387392. Its totient is φ = 14421953059452.

The previous prime is 14434113223391. The next prime is 14434113223447. The reversal of 14434113223421 is 12432231143441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14434113223421 - 2²⁶ = 14434046114557 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14434113223471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6080080205 + ... + 6080082578.

It is an arithmetic number, because the mean of its divisors is an integer number (3611568346848).

Almost surely, 2^{14434113223421} is an apocalyptic number.

It is an amenable number.

14434113223421 is a deficient number, since it is larger than the sum of its proper divisors (12160163971).

14434113223421 is a wasteful number, since it uses less digits than its factorization.

14434113223421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12160163970.

The product of its digits is 55296, while the sum is 35.

Adding to 14434113223421 its reverse (12432231143441), we get a palindrome (26866344366862).

The spelling of 14434113223421 in words is "fourteen trillion, four hundred thirty-four billion, one hundred thirteen million, two hundred twenty-three thousand, four hundred twenty-one".