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144341143441 = 1113121922131
BaseRepresentation
bin1000011001101101100…
…1110000111110010001
3111210120101022211000121
42012123121300332101
54331102313042231
6150150455350241
713266623322115
oct2063331607621
9453511284017
10144341143441
115623a8a34a0
1223b83682381
13107c4088621
146db3dc5745
153b4bdd1311
hex219b670f91

144341143441 has 4 divisors (see below), whose sum is σ = 157463065584. Its totient is φ = 131219221300.

The previous prime is 144341143439. The next prime is 144341143451.

144341143441 is nontrivially palindromic in base 10.

144341143441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 144341143441 - 21 = 144341143439 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 144341143397 and 144341143406.

It is not an unprimeable number, because it can be changed into a prime (144341143451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6560961055 + ... + 6560961076.

It is an arithmetic number, because the mean of its divisors is an integer number (39365766396).

Almost surely, 2144341143441 is an apocalyptic number.

144341143441 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

144341143441 is a deficient number, since it is larger than the sum of its proper divisors (13121922143).

144341143441 is a wasteful number, since it uses less digits than its factorization.

144341143441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13121922142.

The product of its digits is 36864, while the sum is 34.

It can be divided in two parts, 144341 and 143441, that added together give a palindrome (287782).

The spelling of 144341143441 in words is "one hundred forty-four billion, three hundred forty-one million, one hundred forty-three thousand, four hundred forty-one".

Divisors: 1 11 13121922131 144341143441