Base | Representation |
---|---|
bin | 1000011001101101100… |
… | …1110000111110010010 |
3 | 111210120101022211000122 |
4 | 2012123121300332102 |
5 | 4331102313042232 |
6 | 150150455350242 |
7 | 13266623322116 |
oct | 2063331607622 |
9 | 453511284018 |
10 | 144341143442 |
11 | 5623a8a34a1 |
12 | 23b83682382 |
13 | 107c4088622 |
14 | 6db3dc5746 |
15 | 3b4bdd1312 |
hex | 219b670f92 |
144341143442 has 4 divisors (see below), whose sum is σ = 216511715166. Its totient is φ = 72170571720.
The previous prime is 144341143439. The next prime is 144341143451. The reversal of 144341143442 is 244341143441.
144341143442 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 244341143441 = 251 ⋅973470691.
It can be written as a sum of positive squares in only one way, i.e., 142716972841 + 1624170601 = 377779^2 + 40301^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36085285859 + ... + 36085285862.
Almost surely, 2144341143442 is an apocalyptic number.
144341143442 is a deficient number, since it is larger than the sum of its proper divisors (72170571724).
144341143442 is an equidigital number, since it uses as much as digits as its factorization.
144341143442 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 72170571723.
The product of its digits is 73728, while the sum is 35.
Adding to 144341143442 its reverse (244341143441), we get a palindrome (388682286883).
Subtracting 144341143442 from its reverse (244341143441), we obtain a palindrome (99999999999).
The spelling of 144341143442 in words is "one hundred forty-four billion, three hundred forty-one million, one hundred forty-three thousand, four hundred forty-two".
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