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14436131 is a prime number
BaseRepresentation
bin110111000100…
…011100100011
31000011102122112
4313010130203
512143424011
61233225535
7233463563
oct67043443
930142575
1014436131
118170096
124a022ab
132cb5ab8
141cbada3
15140258b
hexdc4723

14436131 has 2 divisors, whose sum is σ = 14436132. Its totient is φ = 14436130.

The previous prime is 14436083. The next prime is 14436133. The reversal of 14436131 is 13163441.

14436131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14436131 is a prime.

It is a super-2 number, since 2×144361312 = 416803756498322, which contains 22 as substring.

Together with 14436133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14436097 and 14436106.

It is not a weakly prime, because it can be changed into another prime (14436133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7218065 + 7218066.

It is an arithmetic number, because the mean of its divisors is an integer number (7218066).

Almost surely, 214436131 is an apocalyptic number.

14436131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14436131 is an equidigital number, since it uses as much as digits as its factorization.

14436131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 864, while the sum is 23.

The square root of 14436131 is about 3799.4908869479. The cubic root of 14436131 is about 243.4913876930.

Adding to 14436131 its reverse (13163441), we get a palindrome (27599572).

The spelling of 14436131 in words is "fourteen million, four hundred thirty-six thousand, one hundred thirty-one".