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14440133013133 is a prime number
BaseRepresentation
bin1101001000100001101011…
…1111111010111010001101
31220010110111200211121222011
43102020122333322322031
53343041343022410013
650413412221021221
73020156646262552
oct322103277727215
956113450747864
1014440133013133
1146680316a5833
1217527173b4811
13809911076929
1437cc98744a29
151a094ad04c3d
hexd221affae8d

14440133013133 has 2 divisors, whose sum is σ = 14440133013134. Its totient is φ = 14440133013132.

The previous prime is 14440133013127. The next prime is 14440133013169. The reversal of 14440133013133 is 33131033104441.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10540918035684 + 3899214977449 = 3246678^2 + 1974643^2 .

It is a cyclic number.

It is not a de Polignac number, because 14440133013133 - 25 = 14440133013101 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14440133013095 and 14440133013104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14440133013533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7220066506566 + 7220066506567.

It is an arithmetic number, because the mean of its divisors is an integer number (7220066506567).

Almost surely, 214440133013133 is an apocalyptic number.

It is an amenable number.

14440133013133 is a deficient number, since it is larger than the sum of its proper divisors (1).

14440133013133 is an equidigital number, since it uses as much as digits as its factorization.

14440133013133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 14440133013133 its reverse (33131033104441), we get a palindrome (47571166117574).

The spelling of 14440133013133 in words is "fourteen trillion, four hundred forty billion, one hundred thirty-three million, thirteen thousand, one hundred thirty-three".