Base | Representation |
---|---|
bin | 1101001000101000101001… |
… | …1011000100100000101010 |
3 | 1220010122022222102101110202 |
4 | 3102022022123010200222 |
5 | 3343104210103320242 |
6 | 50414321520312202 |
7 | 3020254165645106 |
oct | 322121233044052 |
9 | 56118288371422 |
10 | 14442002401322 |
11 | 4668900942851 |
12 | 1752b59472662 |
13 | 809b4b44cba2 |
14 | 37cdd4b20906 |
15 | 1a0a09eb7932 |
hex | d228a6c482a |
14442002401322 has 4 divisors (see below), whose sum is σ = 21663003601986. Its totient is φ = 7221001200660.
The previous prime is 14442002401271. The next prime is 14442002401327. The reversal of 14442002401322 is 22310420024441.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10363383846841 + 4078618554481 = 3219221^2 + 2019559^2 .
It is not an unprimeable number, because it can be changed into a prime (14442002401327) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3610500600329 + ... + 3610500600332.
Almost surely, 214442002401322 is an apocalyptic number.
14442002401322 is a deficient number, since it is larger than the sum of its proper divisors (7221001200664).
14442002401322 is an equidigital number, since it uses as much as digits as its factorization.
14442002401322 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7221001200663.
The product of its (nonzero) digits is 12288, while the sum is 29.
Adding to 14442002401322 its reverse (22310420024441), we get a palindrome (36752422425763).
The spelling of 14442002401322 in words is "fourteen trillion, four hundred forty-two billion, two million, four hundred one thousand, three hundred twenty-two".
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