14443311420311 has 4 divisors (see below), whose sum is σ = 14481420421800. Its totient is φ = 14405202418824.

The previous prime is 14443311420299. The next prime is 14443311420361. The reversal of 14443311420311 is 11302411334441.

It is a happy number.

14443311420311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14443311420311 is a prime.

It is a super-3 number, since 3×14443311420311³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14443311420361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19054500176 + ... + 19054500933.

It is an arithmetic number, because the mean of its divisors is an integer number (3620355105450).

Almost surely, 2^{14443311420311} is an apocalyptic number.

14443311420311 is a deficient number, since it is larger than the sum of its proper divisors (38109001489).

14443311420311 is an equidigital number, since it uses as much as digits as its factorization.

14443311420311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38109001488.

The product of its (nonzero) digits is 13824, while the sum is 32.

Adding to 14443311420311 its reverse (11302411334441), we get a palindrome (25745722754752).

The spelling of 14443311420311 in words is "fourteen trillion, four hundred forty-three billion, three hundred eleven million, four hundred twenty thousand, three hundred eleven".