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14443315001 is a prime number
BaseRepresentation
bin11010111001110001…
…10111111100111001
31101021120122102102122
431130320313330321
5214034442040001
610345110211025
71020630103043
oct153470677471
941246572378
1014443315001
116141969375
122971053a75
131492407b4b
149b0314a93
15598000b1b
hex35ce37f39

14443315001 has 2 divisors, whose sum is σ = 14443315002. Its totient is φ = 14443315000.

The previous prime is 14443314989. The next prime is 14443315013. The reversal of 14443315001 is 10051334441.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (14443314989) and next prime (14443315013).

It can be written as a sum of positive squares in only one way, i.e., 7500426025 + 6942888976 = 86605^2 + 83324^2 .

It is an emirp because it is prime and its reverse (10051334441) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14443315001 is a prime.

It is a super-2 number, since 2×144433150012 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14443315031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7221657500 + 7221657501.

It is an arithmetic number, because the mean of its divisors is an integer number (7221657501).

Almost surely, 214443315001 is an apocalyptic number.

It is an amenable number.

14443315001 is a deficient number, since it is larger than the sum of its proper divisors (1).

14443315001 is an equidigital number, since it uses as much as digits as its factorization.

14443315001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 26.

Adding to 14443315001 its reverse (10051334441), we get a palindrome (24494649442).

The spelling of 14443315001 in words is "fourteen billion, four hundred forty-three million, three hundred fifteen thousand, one".