144441200341421 has 2 divisors, whose sum is σ = 144441200341422. Its totient is φ = 144441200341420.

The previous prime is 144441200341397. The next prime is 144441200341423. The reversal of 144441200341421 is 124143002144441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 144422469408100 + 18730933321 = 12017590^2 + 136861^2 .

It is a cyclic number.

It is not a de Polignac number, because 144441200341421 - 2⁶ = 144441200341357 is a prime.

Together with 144441200341423, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144441200341423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72220600170710 + 72220600170711.

It is an arithmetic number, because the mean of its divisors is an integer number (72220600170711).

Almost surely, 2^{144441200341421} is an apocalyptic number.

It is an amenable number.

144441200341421 is a deficient number, since it is larger than the sum of its proper divisors (1).

144441200341421 is an equidigital number, since it uses as much as digits as its factorization.

144441200341421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 49152, while the sum is 35.

Adding to 144441200341421 its reverse (124143002144441), we get a palindrome (268584202485862).

The spelling of 144441200341421 in words is "one hundred forty-four trillion, four hundred forty-one billion, two hundred million, three hundred forty-one thousand, four hundred twenty-one".