Base | Representation |
---|---|
bin | 100000110110000100101010… |
… | …110011001101000001001111 |
3 | 200221110121100112211112200012 |
4 | 200312010222303031001033 |
5 | 122413210431400211421 |
6 | 1231120542044023435 |
7 | 42266260516242302 |
oct | 4066045263150117 |
9 | 627417315745605 |
10 | 144453353132111 |
11 | 42033360a52021 |
12 | 1425003b831b7b |
13 | 627ab7b4b040a |
14 | 27958185aab39 |
15 | 11a786acd095b |
hex | 83612accd04f |
144453353132111 has 2 divisors, whose sum is σ = 144453353132112. Its totient is φ = 144453353132110.
The previous prime is 144453353132107. The next prime is 144453353132113. The reversal of 144453353132111 is 111231353354441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 144453353132111 - 22 = 144453353132107 is a prime.
It is a super-2 number, since 2×1444533531321112 (a number of 29 digits) contains 22 as substring.
Together with 144453353132113, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (144453353132113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72226676566055 + 72226676566056.
It is an arithmetic number, because the mean of its divisors is an integer number (72226676566056).
Almost surely, 2144453353132111 is an apocalyptic number.
144453353132111 is a deficient number, since it is larger than the sum of its proper divisors (1).
144453353132111 is an equidigital number, since it uses as much as digits as its factorization.
144453353132111 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 259200, while the sum is 41.
The spelling of 144453353132111 in words is "one hundred forty-four trillion, four hundred fifty-three billion, three hundred fifty-three million, one hundred thirty-two thousand, one hundred eleven".
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