1445412013 has 4 divisors (see below), whose sum is σ = 1446604828. Its totient is φ = 1444219200.

The previous prime is 1445411999. The next prime is 1445412077. The reversal of 1445412013 is 3102145441.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3102145441 = 34361 ⋅90281.

It can be written as a sum of positive squares in 2 ways, for example, as 299047849 + 1146364164 = 17293^2 + 33858^2 .

It is a cyclic number.

It is not a de Polignac number, because 1445412013 - 2⁹ = 1445411501 is a prime.

It is a super-3 number, since 3×1445412013³ (a number of 28 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1445412083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 594588 + ... + 597013.

It is an arithmetic number, because the mean of its divisors is an integer number (361651207).

Almost surely, 2^1445412013 is an apocalyptic number.

It is an amenable number.

1445412013 is a deficient number, since it is larger than the sum of its proper divisors (1192815).

1445412013 is a wasteful number, since it uses less digits than its factorization.

1445412013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1192814.

The product of its (nonzero) digits is 1920, while the sum is 25.

The square root of 1445412013 is about 38018.5745787503. The cubic root of 1445412013 is about 1130.6561602750.

Adding to 1445412013 its reverse (3102145441), we get a palindrome (4547557454).

The spelling of 1445412013 in words is "one billion, four hundred forty-five million, four hundred twelve thousand, thirteen".