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144542550113 = 1314683757247
BaseRepresentation
bin1000011010011101101…
…0000100100001100001
3111211002102022100000222
42012213122010201201
54332010343100423
6150222452252425
713304620255433
oct2064732044141
9454072270028
10144542550113
1156333557295
122401b011115
1310826a15c80
146dd2a52653
153b5e9173c8
hex21a7684861

144542550113 has 8 divisors (see below), whose sum is σ = 155672014848. Its totient is φ = 133414629264.

The previous prime is 144542550049. The next prime is 144542550157. The reversal of 144542550113 is 311055245441.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 144542550113 - 26 = 144542550049 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (144542550193) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 187745 + ... + 569502.

It is an arithmetic number, because the mean of its divisors is an integer number (19459001856).

Almost surely, 2144542550113 is an apocalyptic number.

144542550113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

144542550113 is a deficient number, since it is larger than the sum of its proper divisors (11129464735).

144542550113 is a wasteful number, since it uses less digits than its factorization.

144542550113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 771943.

The product of its (nonzero) digits is 48000, while the sum is 35.

Adding to 144542550113 its reverse (311055245441), we get a palindrome (455597795554).

The spelling of 144542550113 in words is "one hundred forty-four billion, five hundred forty-two million, five hundred fifty thousand, one hundred thirteen".

Divisors: 1 13 14683 190879 757247 9844211 11118657701 144542550113