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14481894149 is a prime number
BaseRepresentation
bin11010111110011000…
…00010101100000101
31101101021020110001222
431133030002230011
5214124331103044
610353005130125
71021606032512
oct153714025405
941337213058
1014481894149
116161719468
122981b59945
13149a3c4a48
149b54b8309
1559b5c18ee
hex35f302b05

14481894149 has 2 divisors, whose sum is σ = 14481894150. Its totient is φ = 14481894148.

The previous prime is 14481894137. The next prime is 14481894151. The reversal of 14481894149 is 94149818441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12080208100 + 2401686049 = 109910^2 + 49007^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14481894149 is a prime.

Together with 14481894151, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14481894149.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14481894109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7240947074 + 7240947075.

It is an arithmetic number, because the mean of its divisors is an integer number (7240947075).

Almost surely, 214481894149 is an apocalyptic number.

It is an amenable number.

14481894149 is a deficient number, since it is larger than the sum of its proper divisors (1).

14481894149 is an equidigital number, since it uses as much as digits as its factorization.

14481894149 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1327104, while the sum is 53.

The spelling of 14481894149 in words is "fourteen billion, four hundred eighty-one million, eight hundred ninety-four thousand, one hundred forty-nine".