Search a number
-
+
14500341111 = 34833447037
BaseRepresentation
bin11011000000100100…
…11010010101110111
31101102112221122112210
431200102122111313
5214144041403421
610354504344503
71022221602654
oct154022322567
941375848483
1014500341111
116171078993
122988175133
1314a11832c9
149b7b1ac2b
1559d017576
hex36049a577

14500341111 has 4 divisors (see below), whose sum is σ = 19333788152. Its totient is φ = 9666894072.

The previous prime is 14500341103. The next prime is 14500341113. The reversal of 14500341111 is 11114300541.

14500341111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 14500341111 - 23 = 14500341103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14500341113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2416723516 + ... + 2416723521.

It is an arithmetic number, because the mean of its divisors is an integer number (4833447038).

Almost surely, 214500341111 is an apocalyptic number.

14500341111 is a deficient number, since it is larger than the sum of its proper divisors (4833447041).

14500341111 is an equidigital number, since it uses as much as digits as its factorization.

14500341111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4833447040.

The product of its (nonzero) digits is 240, while the sum is 21.

Adding to 14500341111 its reverse (11114300541), we get a palindrome (25614641652).

The spelling of 14500341111 in words is "fourteen billion, five hundred million, three hundred forty-one thousand, one hundred eleven".

Divisors: 1 3 4833447037 14500341111