Base | Representation |
---|---|
bin | 10101000110011101010… |
… | …100010001010101011111 |
3 | 12010121211000022121212101 |
4 | 111012131110101111133 |
5 | 142224142042044201 |
6 | 3030050220345531 |
7 | 206522265550135 |
oct | 25063524212537 |
9 | 5117730277771 |
10 | 1450043315551 |
11 | 509a61715a16 |
12 | 1b50406a52a7 |
13 | a697a6315ac |
14 | 5027a9b3755 |
15 | 27abb70dd01 |
hex | 1519d51155f |
1450043315551 has 2 divisors, whose sum is σ = 1450043315552. Its totient is φ = 1450043315550.
The previous prime is 1450043315549. The next prime is 1450043315569. The reversal of 1450043315551 is 1555133400541.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1450043315551 - 21 = 1450043315549 is a prime.
Together with 1450043315549, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 1450043315551.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1450043315051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 725021657775 + 725021657776.
It is an arithmetic number, because the mean of its divisors is an integer number (725021657776).
Almost surely, 21450043315551 is an apocalyptic number.
1450043315551 is a deficient number, since it is larger than the sum of its proper divisors (1).
1450043315551 is an equidigital number, since it uses as much as digits as its factorization.
1450043315551 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 90000, while the sum is 37.
The spelling of 1450043315551 in words is "one trillion, four hundred fifty billion, forty-three million, three hundred fifteen thousand, five hundred fifty-one".
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