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14500547115407 is a prime number
BaseRepresentation
bin1101001100000010101111…
…1101011011100110001111
31220100020110001122000020122
43103000223331123212033
53400034110030143112
650501243120535155
73024426034545533
oct323005375334617
956306401560218
1014500547115407
1146907138aaa81
121762377a814bb
1381251b542242
14381b8a1cdbc3
151a22d4aa4872
hexd302bf5b98f

14500547115407 has 2 divisors, whose sum is σ = 14500547115408. Its totient is φ = 14500547115406.

The previous prime is 14500547115389. The next prime is 14500547115409. The reversal of 14500547115407 is 70451174500541.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14500547115407 - 214 = 14500547099023 is a prime.

It is a super-2 number, since 2×145005471154072 (a number of 27 digits) contains 22 as substring.

Together with 14500547115409, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14500547115409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7250273557703 + 7250273557704.

It is an arithmetic number, because the mean of its divisors is an integer number (7250273557704).

Almost surely, 214500547115407 is an apocalyptic number.

14500547115407 is a deficient number, since it is larger than the sum of its proper divisors (1).

14500547115407 is an equidigital number, since it uses as much as digits as its factorization.

14500547115407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 392000, while the sum is 44.

The spelling of 14500547115407 in words is "fourteen trillion, five hundred billion, five hundred forty-seven million, one hundred fifteen thousand, four hundred seven".