145011354461 has 2 divisors, whose sum is σ = 145011354462. Its totient is φ = 145011354460.

The previous prime is 145011354451. The next prime is 145011354463. The reversal of 145011354461 is 164453110541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 73945924900 + 71065429561 = 271930^2 + 266581^2 .

It is a cyclic number.

It is not a de Polignac number, because 145011354461 - 2¹⁰ = 145011353437 is a prime.

It is a super-2 number, since 2×145011354461² (a number of 23 digits) contains 22 as substring.

Together with 145011354463, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (145011354463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72505677230 + 72505677231.

It is an arithmetic number, because the mean of its divisors is an integer number (72505677231).

Almost surely, 2^145011354461 is an apocalyptic number.

It is an amenable number.

145011354461 is a deficient number, since it is larger than the sum of its proper divisors (1).

145011354461 is an equidigital number, since it uses as much as digits as its factorization.

145011354461 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28800, while the sum is 35.

The spelling of 145011354461 in words is "one hundred forty-five billion, eleven million, three hundred fifty-four thousand, four hundred sixty-one".