145011435011 has 2 divisors, whose sum is σ = 145011435012. Its totient is φ = 145011435010.

The previous prime is 145011434999. The next prime is 145011435013. The reversal of 145011435011 is 110534110541.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 145011435011 - 2¹⁴ = 145011418627 is a prime.

Together with 145011435013, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (145011435013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72505717505 + 72505717506.

It is an arithmetic number, because the mean of its divisors is an integer number (72505717506).

Almost surely, 2^145011435011 is an apocalyptic number.

145011435011 is a deficient number, since it is larger than the sum of its proper divisors (1).

145011435011 is an equidigital number, since it uses as much as digits as its factorization.

145011435011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 26.

Adding to 145011435011 its reverse (110534110541), we get a palindrome (255545545552).

The spelling of 145011435011 in words is "one hundred forty-five billion, eleven million, four hundred thirty-five thousand, eleven".