145012433 has 4 divisors (see below), whose sum is σ = 147389748. Its totient is φ = 142635120.

The previous prime is 145012429. The next prime is 145012453. The reversal of 145012433 is 334210541.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 74166544 + 70845889 = 8612^2 + 8417^2 .

It is a cyclic number.

It is not a de Polignac number, because 145012433 - 2² = 145012429 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 145012399 and 145012408.

It is not an unprimeable number, because it can be changed into a prime (145012403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1188566 + ... + 1188687.

It is an arithmetic number, because the mean of its divisors is an integer number (36847437).

Almost surely, 2^145012433 is an apocalyptic number.

It is an amenable number.

145012433 is a deficient number, since it is larger than the sum of its proper divisors (2377315).

145012433 is an equidigital number, since it uses as much as digits as its factorization.

145012433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2377314.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 145012433 is about 12042.1108199518. The cubic root of 145012433 is about 525.3738024197.

Adding to 145012433 its reverse (334210541), we get a palindrome (479222974).

The spelling of 145012433 in words is "one hundred forty-five million, twelve thousand, four hundred thirty-three".