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145014347 is a prime number
BaseRepresentation
bin10001010010010…
…11111001001011
3101002212111021202
420221023321023
5244110424342
622220054415
73410413232
oct1051137113
9332774252
10145014347
1174947475
124069440b
132407480a
141538bb19
15cae7332
hex8a4be4b

145014347 has 2 divisors, whose sum is σ = 145014348. Its totient is φ = 145014346.

The previous prime is 145014341. The next prime is 145014349. The reversal of 145014347 is 743410541.

It is a happy number.

145014347 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-145014347 is a prime.

Together with 145014349, it forms a pair of twin primes.

It is a Chen prime.

It is an alternating number because its digits alternate between odd and even.

It is not a weakly prime, because it can be changed into another prime (145014341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72507173 + 72507174.

It is an arithmetic number, because the mean of its divisors is an integer number (72507174).

Almost surely, 2145014347 is an apocalyptic number.

145014347 is a deficient number, since it is larger than the sum of its proper divisors (1).

145014347 is an equidigital number, since it uses as much as digits as its factorization.

145014347 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6720, while the sum is 29.

The square root of 145014347 is about 12042.1902908067. The cubic root of 145014347 is about 525.3761138561.

Adding to 145014347 its reverse (743410541), we get a palindrome (888424888).

The spelling of 145014347 in words is "one hundred forty-five million, fourteen thousand, three hundred forty-seven".