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145033012240033 = 236305783140871
BaseRepresentation
bin100000111110100000100001…
…001011001101111010100001
3201000112000112222201012220011
4200332200201023031322201
5123002210102113140113
61232243125050244521
742356201150332051
oct4076404113157241
9630460488635804
10145033012240033
1142237178452305
1214324452426741
1362c0728c485b8
1427b58c718d561
1511b7994ee763d
hex83e8212cdea1

145033012240033 has 4 divisors (see below), whose sum is σ = 151338795380928. Its totient is φ = 138727229099140.

The previous prime is 145033012240003. The next prime is 145033012240063. The reversal of 145033012240033 is 330042210330541.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (145033012240003) and next prime (145033012240063).

It is a cyclic number.

It is not a de Polignac number, because 145033012240033 - 225 = 145032978685601 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 145033012239977 and 145033012240004.

It is not an unprimeable number, because it can be changed into a prime (145033012240003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3152891570413 + ... + 3152891570458.

It is an arithmetic number, because the mean of its divisors is an integer number (37834698845232).

Almost surely, 2145033012240033 is an apocalyptic number.

It is an amenable number.

145033012240033 is a deficient number, since it is larger than the sum of its proper divisors (6305783140895).

145033012240033 is an equidigital number, since it uses as much as digits as its factorization.

145033012240033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6305783140894.

The product of its (nonzero) digits is 25920, while the sum is 31.

Adding to 145033012240033 its reverse (330042210330541), we get a palindrome (475075222570574).

The spelling of 145033012240033 in words is "one hundred forty-five trillion, thirty-three billion, twelve million, two hundred forty thousand, thirty-three".

Divisors: 1 23 6305783140871 145033012240033