Base | Representation |
---|---|
bin | 10101000111011110001… |
… | …010100110010011010111 |
3 | 12010201121211112220121211 |
4 | 111013132022212103113 |
5 | 142233404103032111 |
6 | 3030350203522251 |
7 | 206561246344501 |
oct | 25073612462327 |
9 | 5121554486554 |
10 | 1451131299031 |
11 | 50a46a873017 |
12 | 1b52a4b29387 |
13 | a6ac1b658bb |
14 | 503412a4d71 |
15 | 27b31ebe521 |
hex | 151de2a64d7 |
1451131299031 has 4 divisors (see below), whose sum is σ = 1461723498432. Its totient is φ = 1440539099632.
The previous prime is 1451131298993. The next prime is 1451131299047. The reversal of 1451131299031 is 1309921311541.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1451131299031 - 211 = 1451131296983 is a prime.
It is a super-2 number, since 2×14511312990312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1451131249031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5296099495 + ... + 5296099768.
It is an arithmetic number, because the mean of its divisors is an integer number (365430874608).
Almost surely, 21451131299031 is an apocalyptic number.
1451131299031 is a deficient number, since it is larger than the sum of its proper divisors (10592199401).
1451131299031 is a wasteful number, since it uses less digits than its factorization.
1451131299031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10592199400.
The product of its (nonzero) digits is 29160, while the sum is 40.
The spelling of 1451131299031 in words is "one trillion, four hundred fifty-one billion, one hundred thirty-one million, two hundred ninety-nine thousand, thirty-one".
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