Base | Representation |
---|---|
bin | 11011000001111000… |
… | …10011000000111111 |
3 | 1101110022121111022221 |
4 | 31200330103000333 |
5 | 214204344234101 |
6 | 10355535550211 |
7 | 1022414123515 |
oct | 154074230077 |
9 | 41408544287 |
10 | 14511321151 |
11 | 61772983a8 |
12 | 298b98b367 |
13 | 14a3528c82 |
14 | 9b93784b5 |
15 | 59de85aa1 |
hex | 360f1303f |
14511321151 has 2 divisors, whose sum is σ = 14511321152. Its totient is φ = 14511321150.
The previous prime is 14511321113. The next prime is 14511321163. The reversal of 14511321151 is 15112311541.
14511321151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14511321151 - 221 = 14509223999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14511327151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7255660575 + 7255660576.
It is an arithmetic number, because the mean of its divisors is an integer number (7255660576).
Almost surely, 214511321151 is an apocalyptic number.
14511321151 is a deficient number, since it is larger than the sum of its proper divisors (1).
14511321151 is an equidigital number, since it uses as much as digits as its factorization.
14511321151 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 600, while the sum is 25.
Adding to 14511321151 its reverse (15112311541), we get a palindrome (29623632692).
The spelling of 14511321151 in words is "fourteen billion, five hundred eleven million, three hundred twenty-one thousand, one hundred fifty-one".
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