Base | Representation |
---|---|
bin | 10101000111011110011… |
… | …010110100011001001111 |
3 | 12010201122010112221022012 |
4 | 111013132122310121033 |
5 | 142233411200113210 |
6 | 3030350435011435 |
7 | 206561330444201 |
oct | 25073632643117 |
9 | 5121563487265 |
10 | 1451135551055 |
11 | 50a472207693 |
12 | 1b52a6439b7b |
13 | a6ac29c40a8 |
14 | 50341a90771 |
15 | 27b3255e305 |
hex | 151de6b464f |
1451135551055 has 16 divisors (see below), whose sum is σ = 1745525134080. Its totient is φ = 1158134926848.
The previous prime is 1451135551049. The next prime is 1451135551067. The reversal of 1451135551055 is 5501555311541.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1451135551055 is a prime.
It is a super-2 number, since 2×14511355510552 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7988519 + ... + 8168151.
It is an arithmetic number, because the mean of its divisors is an integer number (109095320880).
Almost surely, 21451135551055 is an apocalyptic number.
1451135551055 is a deficient number, since it is larger than the sum of its proper divisors (294389583025).
1451135551055 is a wasteful number, since it uses less digits than its factorization.
1451135551055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 183490.
The product of its (nonzero) digits is 187500, while the sum is 41.
The spelling of 1451135551055 in words is "one trillion, four hundred fifty-one billion, one hundred thirty-five million, five hundred fifty-one thousand, fifty-five".
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