145144345052141 has 4 divisors (see below), whose sum is σ = 145144477282752. Its totient is φ = 145144212821532.

The previous prime is 145144345052051. The next prime is 145144345052173. The reversal of 145144345052141 is 141250543441541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-145144345052141 is a prime.

It is a super-2 number, since 2×145144345052141² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 145144345052092 and 145144345052101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145144345052191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64454915 + ... + 66668768.

It is an arithmetic number, because the mean of its divisors is an integer number (36286119320688).

Almost surely, 2^{145144345052141} is an apocalyptic number.

It is an amenable number.

145144345052141 is a deficient number, since it is larger than the sum of its proper divisors (132230611).

145144345052141 is a wasteful number, since it uses less digits than its factorization.

145144345052141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 132230610.

The product of its (nonzero) digits is 768000, while the sum is 44.

Adding to 145144345052141 its reverse (141250543441541), we get a palindrome (286394888493682).

The spelling of 145144345052141 in words is "one hundred forty-five trillion, one hundred forty-four billion, three hundred forty-five million, fifty-two thousand, one hundred forty-one".