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145201703 is a prime number
BaseRepresentation
bin10001010011110…
…01101000100111
3101010020000021212
420221321220213
5244132423303
622224102035
73412123403
oct1051715047
9333200255
10145201703
1174a65209
124076491b
132410bb8a
14153da103
15cb32ad8
hex8a79a27

145201703 has 2 divisors, whose sum is σ = 145201704. Its totient is φ = 145201702.

The previous prime is 145201687. The next prime is 145201759. The reversal of 145201703 is 307102541.

145201703 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (307102541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 145201703 - 24 = 145201687 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (145201103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72600851 + 72600852.

It is an arithmetic number, because the mean of its divisors is an integer number (72600852).

Almost surely, 2145201703 is an apocalyptic number.

145201703 is a deficient number, since it is larger than the sum of its proper divisors (1).

145201703 is an equidigital number, since it uses as much as digits as its factorization.

145201703 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 840, while the sum is 23.

The square root of 145201703 is about 12049.9669294152. The cubic root of 145201703 is about 525.6022754018.

The spelling of 145201703 in words is "one hundred forty-five million, two hundred one thousand, seven hundred three".