145212433 has 2 divisors, whose sum is σ = 145212434. Its totient is φ = 145212432.

The previous prime is 145212427. The next prime is 145212439. The reversal of 145212433 is 334212541.

It is a balanced prime because it is at equal distance from previous prime (145212427) and next prime (145212439).

It can be written as a sum of positive squares in only one way, i.e., 135769104 + 9443329 = 11652^2 + 3073^2 .

It is a cyclic number.

It is not a de Polignac number, because 145212433 - 2¹⁷ = 145081361 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 145212398 and 145212407.

It is not a weakly prime, because it can be changed into another prime (145212439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72606216 + 72606217.

It is an arithmetic number, because the mean of its divisors is an integer number (72606217).

Almost surely, 2^145212433 is an apocalyptic number.

It is an amenable number.

145212433 is a deficient number, since it is larger than the sum of its proper divisors (1).

145212433 is an equidigital number, since it uses as much as digits as its factorization.

145212433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2880, while the sum is 25.

The square root of 145212433 is about 12050.4121506279. The cubic root of 145212433 is about 525.6152219293.

Adding to 145212433 its reverse (334212541), we get a palindrome (479424974).

The spelling of 145212433 in words is "one hundred forty-five million, two hundred twelve thousand, four hundred thirty-three".