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145220214493 is a prime number
BaseRepresentation
bin1000011100111111001…
…1001001111011011101
3111212211122110020210201
42013033303021323131
54334402333330433
6150414021103501
713330456312354
oct2071763117335
9455748406721
10145220214493
11566510305a2
1224189b57b91
1310904234b03
147058a5499b
153b9e176a7d
hex21cfcc9edd

145220214493 has 2 divisors, whose sum is σ = 145220214494. Its totient is φ = 145220214492.

The previous prime is 145220214481. The next prime is 145220214509. The reversal of 145220214493 is 394412022541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131059928484 + 14160286009 = 362022^2 + 118997^2 .

It is a cyclic number.

It is not a de Polignac number, because 145220214493 - 233 = 136630279901 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (145220214413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72610107246 + 72610107247.

It is an arithmetic number, because the mean of its divisors is an integer number (72610107247).

Almost surely, 2145220214493 is an apocalyptic number.

It is an amenable number.

145220214493 is a deficient number, since it is larger than the sum of its proper divisors (1).

145220214493 is an equidigital number, since it uses as much as digits as its factorization.

145220214493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69120, while the sum is 37.

The spelling of 145220214493 in words is "one hundred forty-five billion, two hundred twenty million, two hundred fourteen thousand, four hundred ninety-three".