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145254510103 = 347671417793
BaseRepresentation
bin1000011101000111010…
…1111110111000010111
3111212221000222122112111
42013101311332320113
54334440123310403
6150421244131451
713331353651513
oct2072165767027
9455830878474
10145254510103
115666942537a
1224199536b87
131090b382081
14705d421143
153ba219d56d
hex21d1d7ee17

145254510103 has 4 divisors (see below), whose sum is σ = 145255275568. Its totient is φ = 145253744640.

The previous prime is 145254510073. The next prime is 145254510131. The reversal of 145254510103 is 301015452541.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 145254510103 - 221 = 145252412951 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145254510143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 138775 + ... + 556567.

It is an arithmetic number, because the mean of its divisors is an integer number (36313818892).

Almost surely, 2145254510103 is an apocalyptic number.

145254510103 is a deficient number, since it is larger than the sum of its proper divisors (765465).

145254510103 is an equidigital number, since it uses as much as digits as its factorization.

145254510103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 765464.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 145254510103 its reverse (301015452541), we get a palindrome (446269962644).

The spelling of 145254510103 in words is "one hundred forty-five billion, two hundred fifty-four million, five hundred ten thousand, one hundred three".

Divisors: 1 347671 417793 145254510103