1452625231 has 4 divisors (see below), whose sum is σ = 1538073792. Its totient is φ = 1367176672.

The previous prime is 1452625211. The next prime is 1452625241. The reversal of 1452625231 is 1325262541.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1325262541 = 809 ⋅1638149.

It is a cyclic number.

It is not a de Polignac number, because 1452625231 - 2⁷ = 1452625103 is a prime.

It is a super-2 number, since 2×1452625231² = 4220240123475606722, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1452625193 and 1452625202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1452625211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42724255 + ... + 42724288.

It is an arithmetic number, because the mean of its divisors is an integer number (384518448).

Almost surely, 2^1452625231 is an apocalyptic number.

1452625231 is a deficient number, since it is larger than the sum of its proper divisors (85448561).

1452625231 is an equidigital number, since it uses as much as digits as its factorization.

1452625231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 85448560.

The product of its digits is 14400, while the sum is 31.

The square root of 1452625231 is about 38113.3209127727. The cubic root of 1452625231 is about 1132.5338578991.

Adding to 1452625231 its reverse (1325262541), we get a palindrome (2777887772).

The spelling of 1452625231 in words is "one billion, four hundred fifty-two million, six hundred twenty-five thousand, two hundred thirty-one".