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145300325143 = 238627732283
BaseRepresentation
bin1000011101010010010…
…0110000001100010111
3111220001020012021221211
42013110210300030113
54340033340401033
6150430002122251
713332451246201
oct2072444601427
9456036167854
10145300325143
1156692277946
12241b0950387
1310917a0366c
147065549771
153ba61ed2cd
hex21d4930317

145300325143 has 8 divisors (see below), whose sum is σ = 151635512448. Its totient is φ = 138966619704.

The previous prime is 145300325119. The next prime is 145300325221. The reversal of 145300325143 is 341523003541.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 145300325143 - 213 = 145300316951 is a prime.

It is a super-2 number, since 2×1453003251432 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145300325743) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 167721 + ... + 564562.

It is an arithmetic number, because the mean of its divisors is an integer number (18954439056).

Almost surely, 2145300325143 is an apocalyptic number.

145300325143 is a deficient number, since it is larger than the sum of its proper divisors (6335187305).

145300325143 is an equidigital number, since it uses as much as digits as its factorization.

145300325143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 740933.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 145300325143 its reverse (341523003541), we get a palindrome (486823328684).

The spelling of 145300325143 in words is "one hundred forty-five billion, three hundred million, three hundred twenty-five thousand, one hundred forty-three".

Divisors: 1 23 8627 198421 732283 16842509 6317405441 145300325143