145301201111 has 4 divisors (see below), whose sum is σ = 158510401224. Its totient is φ = 132092001000.

The previous prime is 145301201107. The next prime is 145301201113. The reversal of 145301201111 is 111102103541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 145301201111 - 2² = 145301201107 is a prime.

It is a super-2 number, since 2×145301201111² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145301201113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6604600040 + ... + 6604600061.

It is an arithmetic number, because the mean of its divisors is an integer number (39627600306).

Almost surely, 2^145301201111 is an apocalyptic number.

145301201111 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

145301201111 is a deficient number, since it is larger than the sum of its proper divisors (13209200113).

145301201111 is a wasteful number, since it uses less digits than its factorization.

145301201111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13209200112.

The product of its (nonzero) digits is 120, while the sum is 20.

Adding to 145301201111 its reverse (111102103541), we get a palindrome (256403304652).

The spelling of 145301201111 in words is "one hundred forty-five billion, three hundred one million, two hundred one thousand, one hundred eleven".