1453406473 has 4 divisors (see below), whose sum is σ = 1453483728. Its totient is φ = 1453329220.

The previous prime is 1453406459. The next prime is 1453406477. The reversal of 1453406473 is 3746043541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 1453406473 - 2⁵ = 1453406441 is a prime.

It is a super-2 number, since 2×1453406473² = 4224780751516599458, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1453406477) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9990 + ... + 54832.

It is an arithmetic number, because the mean of its divisors is an integer number (363370932).

Almost surely, 2^1453406473 is an apocalyptic number.

It is an amenable number.

1453406473 is a deficient number, since it is larger than the sum of its proper divisors (77255).

1453406473 is an equidigital number, since it uses as much as digits as its factorization.

1453406473 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 77254.

The product of its (nonzero) digits is 120960, while the sum is 37.

The square root of 1453406473 is about 38123.5684714849. The cubic root of 1453406473 is about 1132.7368523188.

The spelling of 1453406473 in words is "one billion, four hundred fifty-three million, four hundred six thousand, four hundred seventy-three".