14540000103113 has 2 divisors, whose sum is σ = 14540000103114. Its totient is φ = 14540000103112.

The previous prime is 14540000102989. The next prime is 14540000103227. The reversal of 14540000103113 is 31130100004541.

It is a happy number.

14540000103113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14505228296329 + 34771806784 = 3808573^2 + 186472^2 .

It is an emirp because it is prime and its reverse (31130100004541) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14540000103113 is a prime.

It is a super-2 number, since 2×14540000103113² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14540000103313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7270000051556 + 7270000051557.

It is an arithmetic number, because the mean of its divisors is an integer number (7270000051557).

Almost surely, 2^{14540000103113} is an apocalyptic number.

It is an amenable number.

14540000103113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14540000103113 is an equidigital number, since it uses as much as digits as its factorization.

14540000103113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 14540000103113 its reverse (31130100004541), we get a palindrome (45670100107654).

The spelling of 14540000103113 in words is "fourteen trillion, five hundred forty billion, one hundred three thousand, one hundred thirteen".