Base | Representation |
---|---|
bin | 11011000101010100… |
… | …11110100011011011 |
3 | 1101112022221220111101 |
4 | 31202222132203123 |
5 | 214234243014001 |
6 | 10402451012231 |
7 | 1023214461016 |
oct | 154252364333 |
9 | 41468856441 |
10 | 14540204251 |
11 | 6191625731 |
12 | 299959a077 |
13 | 14a94cc771 |
14 | 9bd13637d |
15 | 5a178da01 |
hex | 362a9e8db |
14540204251 has 2 divisors, whose sum is σ = 14540204252. Its totient is φ = 14540204250.
The previous prime is 14540204249. The next prime is 14540204269. The reversal of 14540204251 is 15240204541.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14540204251 - 21 = 14540204249 is a prime.
It is a super-2 number, since 2×145402042512 (a number of 21 digits) contains 22 as substring.
Together with 14540204249, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (14540204051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7270102125 + 7270102126.
It is an arithmetic number, because the mean of its divisors is an integer number (7270102126).
Almost surely, 214540204251 is an apocalyptic number.
14540204251 is a deficient number, since it is larger than the sum of its proper divisors (1).
14540204251 is an equidigital number, since it uses as much as digits as its factorization.
14540204251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6400, while the sum is 28.
Adding to 14540204251 its reverse (15240204541), we get a palindrome (29780408792).
It can be divided in two parts, 14540 and 204251, that added together give a triangular number (218791 = T661).
The spelling of 14540204251 in words is "fourteen billion, five hundred forty million, two hundred four thousand, two hundred fifty-one".
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