14540340041 has 4 divisors (see below), whose sum is σ = 14541261312. Its totient is φ = 14539418772.

The previous prime is 14540340029. The next prime is 14540340127. The reversal of 14540340041 is 14004304541.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14004304541 = 4759 ⋅2942699.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14540340041 is a prime.

It is a super-2 number, since 2×14540340041² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14540340341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 436541 + ... + 468666.

It is an arithmetic number, because the mean of its divisors is an integer number (3635315328).

Almost surely, 2^14540340041 is an apocalyptic number.

It is an amenable number.

14540340041 is a deficient number, since it is larger than the sum of its proper divisors (921271).

14540340041 is an equidigital number, since it uses as much as digits as its factorization.

14540340041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 921270.

The product of its (nonzero) digits is 3840, while the sum is 26.

Adding to 14540340041 its reverse (14004304541), we get a palindrome (28544644582).

The spelling of 14540340041 in words is "fourteen billion, five hundred forty million, three hundred forty thousand, forty-one".