Base | Representation |
---|---|
bin | 11011000101010101… |
… | …11111101110011111 |
3 | 1101112100012210212211 |
4 | 31202222333232133 |
5 | 214234311341002 |
6 | 10402453541251 |
7 | 1023215565115 |
oct | 154252775637 |
9 | 41470183784 |
10 | 14540340127 |
11 | 6191708825 |
12 | 2999644827 |
13 | 14a9549571 |
14 | 9bd16dab5 |
15 | 5a17b8dd7 |
hex | 362abfb9f |
14540340127 has 2 divisors, whose sum is σ = 14540340128. Its totient is φ = 14540340126.
The previous prime is 14540340029. The next prime is 14540340149. The reversal of 14540340127 is 72104304541.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14540340127 - 219 = 14539815839 is a prime.
It is a super-2 number, since 2×145403401272 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14540340167) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7270170063 + 7270170064.
It is an arithmetic number, because the mean of its divisors is an integer number (7270170064).
Almost surely, 214540340127 is an apocalyptic number.
14540340127 is a deficient number, since it is larger than the sum of its proper divisors (1).
14540340127 is an equidigital number, since it uses as much as digits as its factorization.
14540340127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13440, while the sum is 31.
Adding to 14540340127 its reverse (72104304541), we get a palindrome (86644644668).
The spelling of 14540340127 in words is "fourteen billion, five hundred forty million, three hundred forty thousand, one hundred twenty-seven".
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