Base | Representation |
---|---|
bin | 11011000101010110… |
… | …00000100010001011 |
3 | 1101112100012222102100 |
4 | 31202223000202023 |
5 | 214234311442220 |
6 | 10402454004443 |
7 | 1023215610552 |
oct | 154253004213 |
9 | 41470188370 |
10 | 14540343435 |
11 | 6191710262 |
12 | 2999646723 |
13 | 14a954ac17 |
14 | 9bd170d99 |
15 | 5a17b9d90 |
hex | 362ac088b |
14540343435 has 48 divisors (see below), whose sum is σ = 27009912384. Its totient is φ = 7217185536.
The previous prime is 14540343407. The next prime is 14540343469. The reversal of 14540343435 is 53434304541.
14540343435 is a `hidden beast` number, since 145 + 40 + 3 + 43 + 435 = 666.
It is not a de Polignac number, because 14540343435 - 218 = 14540081291 is a prime.
It is a super-2 number, since 2×145403434352 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 14540343435.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 151552 + ... + 228141.
It is an arithmetic number, because the mean of its divisors is an integer number (562706508).
Almost surely, 214540343435 is an apocalyptic number.
14540343435 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14540343435 is a deficient number, since it is larger than the sum of its proper divisors (12469568949).
14540343435 is a wasteful number, since it uses less digits than its factorization.
14540343435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 379764 (or 379761 counting only the distinct ones).
The product of its (nonzero) digits is 172800, while the sum is 36.
Adding to 14540343435 its reverse (53434304541), we get a palindrome (67974647976).
The spelling of 14540343435 in words is "fourteen billion, five hundred forty million, three hundred forty-three thousand, four hundred thirty-five".
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