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145411205215 = 529082241043
BaseRepresentation
bin1000011101101100101…
…1101110100001011111
3111220022221211120211011
42013123023232201133
54340300232031330
6150445002440051
713335265564543
oct2073313564137
9456287746734
10145411205215
115673991a771
1224221b03027
1310934986483
14707616da23
153bb0d0182a
hex21db2ee85f

145411205215 has 4 divisors (see below), whose sum is σ = 174493446264. Its totient is φ = 116328964168.

The previous prime is 145411205161. The next prime is 145411205227. The reversal of 145411205215 is 512502114541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 145411205215 - 27 = 145411205087 is a prime.

It is a super-2 number, since 2×1454112052152 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14541120517 + ... + 14541120526.

It is an arithmetic number, because the mean of its divisors is an integer number (43623361566).

Almost surely, 2145411205215 is an apocalyptic number.

145411205215 is a deficient number, since it is larger than the sum of its proper divisors (29082241049).

145411205215 is an equidigital number, since it uses as much as digits as its factorization.

145411205215 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29082241048.

The product of its (nonzero) digits is 8000, while the sum is 31.

Adding to 145411205215 its reverse (512502114541), we get a palindrome (657913319756).

The spelling of 145411205215 in words is "one hundred forty-five billion, four hundred eleven million, two hundred five thousand, two hundred fifteen".

Divisors: 1 5 29082241043 145411205215